A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10 m/s² in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

 -Shresthi  Goyal, Subject Matter Expert at Edumarz

Answer:

u = 5m/s

v= 0 ( because the stone will reach a position of rest)

a = -10m/s²

t=?

s=?

[Since, v² – u² = 2as]

[Therefore, s= (v² – u²)/2a]

Substituting the values

s = [0 – (5)²]/[2 × (-10)]

s= (-25)/(-20)

s = 1.25m

So, height attained is 1.25m

Now,[ since, V = u + at]

0 = 5 + (-10)×t

0 = 5 – 10t

-5 = -10t

5/10 = t

t = 0.5 seconds