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In each of the following a force, F is acting on an object of mass, m. The direction of displacement is from west to east shown by the longer arrow. Observe the diagrams carefully and state whether the work done by the force is negative, positive or zero.

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Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.

W = (F cos θ) d 

Where,

  • W is the work done by the force.
  • F is the force, d is the displacement caused by the force
  • θ is the angle between the force vector and the displacement vector

Case I – In this case, the direction of force acting on the block is perpendicular to the displacement. Therefore, work done by force on the block will be zero.

W = F × cos θ × d

The angle between the force and displacement is 90o.

W = F × cos 90 × d

W = 0 (since cos 90 = 0)

Case II – In this case, the direction of force acting on the block is in the direction of displacement. Therefore, work done by force on the block will be positive.

W = F × cos θ × d

The angle between the force and displacement is 0o.

W = F × cos 0 × d

W = F × d (since cos 0 = 1)

Case III – In this case, the direction of force acting on the block is opposite to the direction of displacement. Therefore, work done by force on the block will be negative.

W = F × cos θ × d

The angle between the force and displacement is 180o.

W = F × cos 180o × d

W = – F × d (since cos 180o = -1)

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