The kinetic energy of an object of mass, m moving with a velocity of 5 m s–1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

K.E = Kinetic energy attain by object

m = Mass of the object

v = Velocity of the object

Given parameters:

• K.E. of the object = 25 J
• Velocity of the object ( v) = 5 m/s

K.E=1/2mvv

25=1/2×m×52

50 = 25 × m

m = 2 kg

1st case:

When velocity is doubled, then

v = 10 m/s

m = 2 kg

K.E=1/2mvv

K.E=1/2×2×102

K.E = 102

K.E = 100 J

2nd case:

When velocity is increased three times, then

v = 15 m/s

m = 2 kg

K.E=1/2mvv

K.E=1/2×2×152

K.E = 225 J